Respuesta :

[tex]y=(x^2-2x+6)e^x[/tex]

Differentiate y

so,

[tex]\begin{gathered} y^{\prime}=(2x-2)\cdot e^x+(x^2-2x+6)\cdot e^x \\ y^{\prime}=(2x-2+x^2-2x+6)\cdot e^x \\ y^{\prime}=(x^2+4)\cdot e^x \end{gathered}[/tex]

so, the answer is option 3

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Note: we have used the rule of y = f(x) * g(x)

y' = f'(x) * g(x) + f(x) * g'(x)

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