Differentiate. y = (x2 - 2x + 6) ex O (2x - 2) et O (x2 + 4x + 4) et 0 (x² + 4) ex 03 + 4x + 6 ex 3 400

Differentiate y
so,
[tex]\begin{gathered} y^{\prime}=(2x-2)\cdot e^x+(x^2-2x+6)\cdot e^x \\ y^{\prime}=(2x-2+x^2-2x+6)\cdot e^x \\ y^{\prime}=(x^2+4)\cdot e^x \end{gathered}[/tex]so, the answer is option 3
=======================================================
Note: we have used the rule of y = f(x) * g(x)
y' = f'(x) * g(x) + f(x) * g'(x)