We are given two equations
[tex]-4x+11y=15\qquad eq.1[/tex][tex]x=2y\qquad eq.2[/tex]Let us substitute eq.2 into eq.1
[tex]\begin{gathered} -4x+11y=15 \\ -4(2y)+11y=15 \\ -8y+11y=15 \\ 3y=15 \\ y=\frac{15}{3} \\ y=5 \end{gathered}[/tex]So we found the value of y that is 5.
Now let us substitute the value of y into eq.2
[tex]\begin{gathered} x=2y \\ x=2(5) \\ x=10 \end{gathered}[/tex]So the value of x is 10.
Therefore,
x = 10
y = 5