Consider the graph below that represents the variation of the velocity with respect to time of an object moving along the x - axis . The distance traveled during the second part of the trip ( 10s to 18s ) is equal to :

In a velocity-time graph, the area under the curve represents the distance.
The distance traveled from 10s to 18 s is
[tex]\begin{gathered} d\text{ = }\frac{1}{2}\times10\times(18-10) \\ =\text{ 40 m} \end{gathered}[/tex]Final Answer: The distance traveled is 40 m from time 10 s to 18 s.