Question

Find the second derivative of the function.g(t) = 31t-2g"(t) =X

Answer 1

Let's find the first derivative of the function:

$g^{\prime}(t)=\frac{dg}{dt}=\frac{d}{dt}(31t^{-2})=-2(31)t^{-3}=-62t^{-3}$

Hence the first derivative is:

$\frac{dg}{dt}=-62t^{-3}$

Now, that we have the first derivative we can calculate the second derivative:

$g^{\doubleprime}(t)=\frac{d^2g}{dt^2}=\frac{d}{dt}(-62t^{-3})=-3(-62)t^{-4}=186t^{-4}$

Therefore:

$g^{\doubleprime}(t)=186t^{-4}$