You roll a 6-sided die two times.What is the probability of rolling an odd number and then rolling a 1?Simplify your answer and write it as a fraction or whole number.

The sample space for rolling a die twice is shown below
1,1 1,2 1,3 1,4 1,5 1,6
2,1 2,2 2,3 2,4 2,5 2,6
3,1 3,2 3,3 3,4 3,5 3,6
4,1 4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,2 6,3 6,4 6,5 6,6
Total number of outcomes = 36
Outcomes involving an odd number followed by 1 = 1,1 3,1 5,1
Thus, number of favorable outcomes = 3
Probability = number of favorable outcomes/total number of outcomes
the probability of rolling an odd number and then rolling a 1 = 3/36
the probability of rolling an odd number and then rolling a 1 = 1/12