Question

what are the solutions of3x²+13x+14=0 select two correct answersA 7/3B 2C 7D -7/3E -2

Answer 1

Given the equation:

$3x^{2}+13x+14=0$

using the general formula to find the solutions:

$x=\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2a}$

From the given equation :

a = 3 , b = 13 and c = 14

So,

$\begin{gathered} x=\frac{-13\pm\sqrt[]{13^2-4\cdot3\cdot14}}{2\cdot3}=\frac{-13\pm\sqrt[]{169-168}}{6}=\frac{-13\pm\sqrt[]{1}}{6} \\ x=\frac{-13\pm1}{6} \end{gathered}$

so, x = (-13+1)/6 = -12/6 = -2

OR x = (-13-1)/6 = -14/6 = -7/3

So, the answer is the options: D. -7/3 and E. -2