Question

Suppose a normal distribution has a mean of 62 and a standard deviation of4. What is the probability that a data value is between 58 and 64? Round youranswer to the nearest tenth of a percent.

Answer 1

the mean is 62

the standard deviation is 4

probability of between 58 and 64

z = (x - mean) / SD

z = (58 - 62)/4

z = 0.5

P(-1 < z < 0.5) = 0.5328

0.5328

53.3