Answer:
a. Increasing
b. Increasing
c. Decreasing
Explanation:
Part A (g(x) = 4x – 2)
[tex]\begin{gathered} g(2)=4(2)-2=8-2=6 \\ g(1)=4(1)-2=4-2=2 \\ \frac{g(2)-g(1)}{2-1}=\frac{6-2}{1} \\ =\frac{4}{1} \\ =4 \end{gathered}[/tex]g(x) is increasing since its rate of change is positive.
Part B (f(x) = 3x)
[tex]\begin{gathered} f(2)=3(2)=6 \\ f(1)=3(1)=3 \\ \frac{f(2)-f(1)}{2-1}=\frac{6-3}{1} \\ =\frac{3}{1} \\ =3 \end{gathered}[/tex]f(x) is increasing since its rate of change is positive.
Part C (h(x) = 2-x)
[tex]\begin{gathered} h(2)=2-2=0 \\ h(1)=2-1=1 \\ \frac{h(2)-h(1)}{2-1}=\frac{0-1}{1} \\ =\frac{-1}{1} \\ =-1 \end{gathered}[/tex]h(x) is decreasing since its rate of change is negative.