Solve the right triangle. Select the correct measure of each part of the triangle

Given:
Given that a right angle triangle.
[tex]\begin{gathered} \theta=52.4\degree \\ h=16.7 \end{gathered}[/tex]Required:
To measure the each part of the triangle.
Explanation:
Let the the two sides of triangle are a and o.
Now,
[tex]\begin{gathered} \cos\theta=\frac{a}{h} \\ \\ \cos52.4=\frac{a}{16.7} \\ \\ 0.6101=\frac{a}{16.7} \\ \\ a=0.6101\times16.7 \\ \\ a=10.188 \end{gathered}[/tex]Now we have to find the other side of the triangle.
Clearly the given triangle is right angle, therefore,
[tex]\begin{gathered} h^2=a^2+o^2 \\ \\ 16.7^2=10.188^2+o^2 \\ \\ 278.98=103.795+o^2 \\ \\ o^2=175.184 \\ \\ o=13.23 \end{gathered}[/tex]Final Answer:
The other two sides of triangle are,
[tex]\begin{gathered} 10.188 \\ 13.23 \end{gathered}[/tex]