Respuesta :

Given:

Given that a right angle triangle.

[tex]\begin{gathered} \theta=52.4\degree \\ h=16.7 \end{gathered}[/tex]

Required:

To measure the each part of the triangle.

Explanation:

Let the the two sides of triangle are a and o.

Now,

[tex]\begin{gathered} \cos\theta=\frac{a}{h} \\ \\ \cos52.4=\frac{a}{16.7} \\ \\ 0.6101=\frac{a}{16.7} \\ \\ a=0.6101\times16.7 \\ \\ a=10.188 \end{gathered}[/tex]

Now we have to find the other side of the triangle.

Clearly the given triangle is right angle, therefore,

[tex]\begin{gathered} h^2=a^2+o^2 \\ \\ 16.7^2=10.188^2+o^2 \\ \\ 278.98=103.795+o^2 \\ \\ o^2=175.184 \\ \\ o=13.23 \end{gathered}[/tex]

Final Answer:

The other two sides of triangle are,

[tex]\begin{gathered} 10.188 \\ 13.23 \end{gathered}[/tex]

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