Help with this question, it is one question with 3 parts.

The given function is ,
[tex]f(x)=\frac{x+12}{x-6}[/tex]The inverse of the function is ,
[tex]\begin{gathered} y=\frac{x+12}{x-6} \\ x=\frac{y+12}{y-6} \\ y=\frac{6(x+2)}{x-1} \\ f^{-1}(x)=\frac{6x+12}{x-1} \end{gathered}[/tex]for x ,
[tex]x<1\text{ and x>1 .}[/tex]if x= 1 the function will be undefined.
thus,
[tex]x\ne1[/tex]