Question

Calculate the percent yield of HF in a reaction that had a theoretical yield of 12.79g and an actual yield of 10.41g. Round your answer to the correct number of sig figs

Answer 1

The question requires us to calculate the percent yield of HF in a reaction, given its actual yield (10.41g) and theoretical yield (12.79g).

The percent yield of a chemical process can be calculated as:

$\%yield=\frac{actual\text{ yield (g)}}{\text{theoretical yield (g)}}\times100\%$

Thus, applying the values given by the question, we can calculate the percent yield of HF:

$\%yield=\frac{10.41g}{12.79g}\times100\%=81.39\%$

Therefore, the percent yield in the reaction mentioned is 81.39%. Note that the question provided values with four significant figures, thus our answer must also present four significant figures.