Question

question is in the image Don't graph. I can do that

Answer 1

Given:

$\begin{gathered} f(x)\text{ = }\frac{1}{2}(4)^x \\ g(x)\text{ = -}\frac{1}{2}(4)^x \end{gathered}$

The value of the function at any point is obtained by substituting the point into the function.

f(0):

$\begin{gathered} f(0)\text{ = }\frac{1}{2}(4)^0 \\ =\text{ }\frac{1}{2} \end{gathered}$

f(1):

$\begin{gathered} f(1)\text{ = }\frac{1}{2}(4)^1 \\ =\text{ 2} \end{gathered}$

g(0):

$\begin{gathered} g(0)\text{ = -}\frac{1}{2}(4)^0 \\ =-\frac{1}{2} \end{gathered}$

g(1):

$\begin{gathered} g(1)\text{ = -}\frac{1}{2}(4)^1 \\ =\text{ -2} \end{gathered}$