Question

A coin is flipped and a normal 6 sided die is rolled find the probability of getting a head on the coin and a number greater than 4 on the die

Answer 1

Answer:

$P(C\text{ and D)=}\frac{1}{6}$

Step-by-step explanation:

Probability is represented by the following equation:

$P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}$

Therefore, for this situation:

$\begin{gathered} P(\text{Coin)}=\frac{1}{2} \\ P(\text{Die)}=\frac{2}{6} \end{gathered}$

Since the probability of two events occurring together but independents is represented by the multiplication of the probabilities of the events:

$\begin{gathered} P(C\text{ and D)=}\frac{1}{2}\cdot\frac{2}{6} \\ P(C\text{ and D)=}\frac{1}{6} \end{gathered}$