Question

Number 24 answers: Car A: Equation- cost= $22500-2000tCar B: Equation- cost $22500-1500t.

Answer 1

$\begin{gathered} A=22500-2000t \\ B=22500-1500t \end{gathered}$

To graph the equations we need to find at least two pointd for each equation, for this we can use the y-intercept (t=0) and the x-intercept (Cost=0)

for car A the y intercept is found when t=0

$\begin{gathered} A=22500-2000\cdot0 \\ A=22500 \end{gathered}$

now for the x intercept we make the cost equal to 0

$\begin{gathered} 0=22500-2000t \\ -22500=-2000t \\ t=-\frac{22500}{-2000} \\ t=11.25 \end{gathered}$

for this we have the two points (0,22500) and (11.25,0)

We plot both points and graph

we make the same procedure for car B

$\begin{gathered} B=22500-1500\cdot0 \\ B=22500 \end{gathered}$

then

$\begin{gathered} 0=22500-1500t \\ -22500=-1500t \\ t=-\frac{22500}{-1500} \\ t=15 \end{gathered}$

for this we have the two points (0,22500) and (15,0)

We plot both points and graph

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