Respuesta :

Given the exponential function:

[tex]P(t)=1800(1.03)^t[/tex]

Where P models the population size after t hours. The initial population size can be obtained using t = 0:

[tex]\begin{gathered} P(0)=1800(1.03)^0=1800(1) \\ \therefore P(0)=1800 \end{gathered}[/tex]

The initial population size is 1800.

Now, since the term inside the parentheses is greater than 1, we can conclude that this function represents a growth tendency.

Finally, we can take the ratio between the population size at time t and at time t+1:

[tex]\begin{gathered} \frac{P\left(t+1\right)}{P(t)}=\frac{1800(1.03)^{t+1}}{1800(1.03)t}=1.03=1+0.03 \\ \\ Change:\Delta=|1-\frac{P(t+1)}{P(t)}|=|1-1-0.03|=0.03 \end{gathered}[/tex]

In percent form, the change is 3%

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