If AACB = ADCE, ZABC = 61°,ZBCA = 57°, and ZCDE = 2xDEСx = [?]BEnter

We have two congruent triangles. This means they have corresponding sides and angles.
We assume that DE and AB are parallel segments. Then
Then, we can write:
[tex]\begin{gathered} m\angle\text{ABC}=m\angle\text{CDE} \\ 61=2x \\ x=\frac{61}{2} \\ x=30.5\degree \end{gathered}[/tex]Answer: x = 30.5°