Question

Write an equation of the line perpendicularto the given line that contains P.P (4, 4): y = -2x-8

Answer 1

For this problem we want to find the equation of a line perpendicular to the line y=-2x-8 and passing through the point (4,4). We can see that the slope for the line given is m1=-2 and since we want a perpendicular line we need to satisfy the following:

$m_1\cdot m_2=-1$

And solving for m2 we got:

$m_2=-\frac{1}{m_1}=-\frac{1}{-2}=\frac{1}{2}$

And then with the point given we can find the intercept:

$4=\frac{1}{2}(4)+b$$b=4-2=2$

And the equation for the line would be:

$y=\frac{1}{2}x+2$