The perimeter of a rectangle is 38”. If the length is 3” more than the width, find the width.

Given:
The perimeter of a rectangle is 38”. If the length is 3” more than the width
Required:
Find the width.
Explanation:
We know the perimeter of the rectangle
[tex]\begin{gathered} P=2(l+w) \\ \text{ Where, P perimeter} \\ l\text{ length} \\ w\text{ width} \end{gathered}[/tex]Let width is x, So length will be three 3" more than width. That is x + 3
Now,
[tex]\begin{gathered} P=2(l+w) \\ 2(x+3+x)=38 \\ 2x+3=\frac{38}{2} \\ 2x+3=19 \\ x=8 \end{gathered}[/tex]Width equal 8" and length equal 11"
Answer:
The width is 8". Option B is correct.