Respuesta :

Given:

The perimeter of a rectangle is 38”. If the length is 3” more than the width

Required:

Find the width.

Explanation:

We know the perimeter of the rectangle

[tex]\begin{gathered} P=2(l+w) \\ \text{ Where, P perimeter} \\ l\text{ length} \\ w\text{ width} \end{gathered}[/tex]

Let width is x, So length will be three 3" more than width. That is x + 3

Now,

[tex]\begin{gathered} P=2(l+w) \\ 2(x+3+x)=38 \\ 2x+3=\frac{38}{2} \\ 2x+3=19 \\ x=8 \end{gathered}[/tex]

Width equal 8" and length equal 11"

Answer:

The width is 8". Option B is correct.

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