Question

How do I find the break even for this question?

Answer 1

As given by the question

There are given that the equation

$p=-7x^2+133x-150$

Now,

Solve the above equation for the value of x

So,

$\begin{gathered} p=-7x^2+133x-150 \\ p=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

Then,

$\begin{gathered} p=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ p=\frac{-133\pm\sqrt[]{(133)^2-4\times(-7)\times(-150)}}{2(-7)} \\ p=\frac{-133\pm\sqrt[]{17689^{}-4200}}{-14} \\ p=\frac{133\pm\sqrt[]{13489}}{14} \end{gathered}$

Then,

$\begin{gathered} p=\frac{133\pm\sqrt[]{13489}}{14} \\ p=17.7968,\text{ 1.204} \end{gathered}$

Hence, the 2 tickets price will be, $17.79 and $1.20.