Question

complete the sequence 128,64,a3,16,8,a6,2

Answer 1

Answer:

128, 64, 32, 16, 8, 4,2​

Explanation:

Each next term in the sequence is half of the previous term.

For example,

$64=\frac{128}{2}$$8=\frac{16}{2}$

In a similar fashion, the a_3 term is 1/2 the previous term:

$a_3=\frac{64}{2}$$a_3=32.$

And similarly, a_6 is

$a_6=\frac{8}{2}$

$a_6=4$

Hence, the complete sequence with a_3 = 32 and a_6 = 4 is 128, 64, 32, 16, 8, 4,2​