Question

Find the current in a 5 Ω resistor connected to a battery with an internal resistance of 3 Ω if the emf of the battery is 9 V.4.85 A3.00 A1.13 A1.80 A

Answer 1

Given,

The resistor is R=5 ohm

The internal resistor is r=3 ohm

The voltage is V=9 volt.

Now the current is given by:

$\begin{gathered} I=\frac{V}{R+r} \\ \Rightarrow I=\frac{9}{5+3} \\ \Rightarrow I=1.13A \end{gathered}$

Thus the answer is 1.13 A