A piece of paper has an area of 81 cm².A strip is cut off that is 1/3 the original area. From that strip, another strip is cut off that is 1/3 the area of the first, and so on.Here is a graph and table representing sequence k, where k(n) is the area in square centimeters of the strip of paper after n cuts.Write a recursive definition for this table

A piece of paper has an area of 81 cmA strip is cut off that is 13 the original area From that strip another strip is cut off that is 13 the area of the first a class=

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ANSWER

[tex]a_n=a_{n-1}\cdot\text{ }\frac{1}{3}[/tex]

EXPLANATION

We want to write the recursive definition of the situation represented in the table.

The original area of the paper is 81 cm² and with each strip that is cut off, we are left with 1/3 of the area of the former paper.

We can therefore, say that this situation represents a geometric progression, where the value of the next term can be gotten by multiplying a constant factor to the former term.

The general recursive definition of a geometric progression is given as:

[tex]\begin{gathered} a_n=a_{n\text{ - 1}}\cdot\text{ r} \\ _{}where\text{ an is the nth term} \\ a(n\text{ - 1) is the (n - 1)th term or the term before the nth term} \\ r\text{ = common ratio} \end{gathered}[/tex]

The common ratio is the factor that multiplies each term, as described earlier.

From the question, the common ratio is 1/3, since each new strip is 1/3 the area of the former strip.

Therefore, the recursive definition of the data in the table is:

[tex]a_n=a_{n-1}\cdot\text{ }\frac{1}{3}[/tex]

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