Respuesta :

Given the expression:

[tex]\frac{20ab}{\mleft(a-b\mright)^2}[/tex]

1. You need to substitute these values given in the exercise into the expression:

[tex]\begin{gathered} a=4 \\ b=-2 \end{gathered}[/tex]

Then:

[tex]=\frac{20(4)(-2)}{(4-(-2))^2}[/tex]

2. According to the Sign Rules for Multiplication:

[tex]\begin{gathered} +\cdot+=+ \\ -\cdot-=+ \\ -\cdot+=- \\ +\cdot-=- \end{gathered}[/tex]

Knowing this, you can solve the multiplication in the numerator and simplify the denominator:

[tex]=\frac{-160}{(4+2)^2}[/tex][tex]=\frac{-160}{(6)^2}[/tex]

You know that:

[tex]6^2=6\cdot6=36[/tex]

Then:

[tex]=\frac{-160}{36}[/tex]

3. According to the Sign Rules for Division:

[tex]\begin{gathered} \frac{-}{-}=+ \\ \\ \frac{+}{+}=+ \\ \\ \frac{-}{+}=- \\ \\ \frac{+}{-}=- \end{gathered}[/tex]

Therefore, since the numerator is negative and the denominator is positive, the fraction is negative:

[tex]=-\frac{160}{36}[/tex]

4. You can reduce the fraction by dividing the numerator and the denominator by 4:

[tex]\begin{gathered} =-\frac{160\div4}{36\div4} \\ \\ =-\frac{40}{9} \end{gathered}[/tex]

Hence, the answer is:

[tex]=-\frac{40}{9}[/tex]

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