I need help with this problem Evaluate each expression given the variable replacement

Given the expression:
[tex]\frac{20ab}{\mleft(a-b\mright)^2}[/tex]1. You need to substitute these values given in the exercise into the expression:
[tex]\begin{gathered} a=4 \\ b=-2 \end{gathered}[/tex]Then:
[tex]=\frac{20(4)(-2)}{(4-(-2))^2}[/tex]2. According to the Sign Rules for Multiplication:
[tex]\begin{gathered} +\cdot+=+ \\ -\cdot-=+ \\ -\cdot+=- \\ +\cdot-=- \end{gathered}[/tex]Knowing this, you can solve the multiplication in the numerator and simplify the denominator:
[tex]=\frac{-160}{(4+2)^2}[/tex][tex]=\frac{-160}{(6)^2}[/tex]You know that:
[tex]6^2=6\cdot6=36[/tex]Then:
[tex]=\frac{-160}{36}[/tex]3. According to the Sign Rules for Division:
[tex]\begin{gathered} \frac{-}{-}=+ \\ \\ \frac{+}{+}=+ \\ \\ \frac{-}{+}=- \\ \\ \frac{+}{-}=- \end{gathered}[/tex]Therefore, since the numerator is negative and the denominator is positive, the fraction is negative:
[tex]=-\frac{160}{36}[/tex]4. You can reduce the fraction by dividing the numerator and the denominator by 4:
[tex]\begin{gathered} =-\frac{160\div4}{36\div4} \\ \\ =-\frac{40}{9} \end{gathered}[/tex]Hence, the answer is:
[tex]=-\frac{40}{9}[/tex]