Question

Hi, I need help with problems for review to study before test. Thank you

Answer 1

Answer: -32i - 12i²

Given:

$-4i(8+3i)$

First, we are going to distribute -4i

$=(-4i)(8)+(-4i)(3i)_{}$

Then, we multiply

$=-32i+(-12i^2)$

And then we simplify

$=-32i-12i^2$

The final answer would be -32i - 12i².