We have the following:
[tex]\begin{gathered} -2x-5y=1 \\ 2x+2y=-10 \end{gathered}[/tex]solving using elimination:
[tex]\begin{gathered} -2x-5y=1 \\ + \\ 2x+2y=-10 \\ -2x+2x-5y+2y=1-10 \\ -3y=-9 \\ y=\frac{-9}{-3} \\ y=3 \end{gathered}[/tex]Now, for x:
[tex]\begin{gathered} -2x-5\cdot3=1 \\ -2x-15=1 \\ -2x=16 \\ x=\frac{16}{-2} \\ x=-8 \end{gathered}[/tex]Therefore:
x = -8 and y = 3
