Consider that the area of a triangle with base (b) and height (h) is given by,
[tex]\text{Area of triangle}=\frac{1}{2}\times b\times h[/tex]According to the given problem,
[tex]\begin{gathered} b=56\text{ m} \\ h=56\text{ m} \end{gathered}[/tex]So the area of the triangle becomes,
[tex]\begin{gathered} A_T=\frac{1}{2}\times56\times56 \\ A_T=1568 \end{gathered}[/tex]Consider that the area of the circle with diameter (d) is given by,
[tex]A_C=\frac{\pi}{4}d^2[/tex]According to the given problem,
[tex]d=20\text{ m}[/tex]Then the area of the circle becomes,
[tex]\begin{gathered} A_C=\frac{\pi}{4}(20)^2 \\ A_C=100\pi \\ A_C\approx314.16 \end{gathered}[/tex]Now, the area of the shaded region (A) is calculated as,
[tex]\begin{gathered} A=A_T-A_C \\ A=1568-314.16 \\ A=1253.84 \\ A\approx1254 \end{gathered}[/tex]Thus, the area of the shaded region is 1254 sq. meters approximately.
Therefore, the 3rd option is correct choice.