Question

Solve the following system of linear equations using elimination. x+4y=14 x+3y=11

Answer 1

Answer:

x=2

y=3

Explanation:

Given the system of equations:

$\begin{gathered} x+4y=14 \\ x+3y=11​ \end{gathered}$

Subtract to eliminate x:

$\begin{gathered} (x-x)+(4y-3y)=14-11 \\ 0+y=3 \\ y=3 \end{gathered}$

Next, substitute y=3 to solve for x:

$\begin{gathered} x+4y=14 \\ x+4(3)=14 \\ x+12=14 \\ x=14-12 \\ x=2 \end{gathered}$

The solution to the system is x=2, y=3.