Question

For a confidence level of 99% with a sample size of 11, find the critical t value.

Answer 1

Solution

Given that

sample size n = 11

The degree of freedom df = n - 1 = 11 - 1 = 10

At 99% confidence level,

$\begin{gathered} \alpha=1-99\%=1-0.99=0.01 \\ \\ \frac{\alpha}{2}=0.005 \end{gathered}$

$t_{\frac{\alpha}{2},df}=t_{0.005,10}=3.1693$

Checking the table,

Therefore, the Critical value t value = 3.169