Let F(x) = f(x ^ 9) and G(x) = (f(x)) ^ 9 You also know that a ^ 8 = 15 , f(a) = 2 , f^ prime (a)=7,f^ prime (a^ 9 )=11

Answer:
Explanation:
a) F'(a)
From what we have:
[tex]\begin{gathered} F(x)\text{ = f\lparen x}^9) \\ F(a)\text{ = f\lparen a}^9) \\ F^{\prime}^(A)\text{ = f'\lparen a}^9)\text{ = 11} \\ \end{gathered}[/tex]b) G'(a)
[tex][/tex]