The rule of the area of a sector which has radius r and central angle x degrees is
[tex]A=\frac{x}{360}\times\pi r^2[/tex]Since the central angle is 70 degrees, then
[tex]x=70^{\circ}[/tex]Since the radius of the circle is 6, then
[tex]r=6[/tex]Substitute them in the rule above
[tex]\begin{gathered} A=\frac{70}{360}\times\pi\times6^2 \\ \\ A=\frac{70}{360}\times\pi\times36 \\ \\ A=7\pi \end{gathered}[/tex]The answer is
The area of the sector is 7pi square units