Subtracting 2 from the given equation we get:
[tex]\begin{gathered} -5y+2-2=3x-2, \\ -5y=3x-2. \end{gathered}[/tex]Dividing by -5 we get:
[tex]\begin{gathered} \frac{-5y}{-5}=\frac{3x}{-5}-\frac{2}{-5}, \\ y=-\frac{3}{5}x+\frac{2}{5}\text{.} \end{gathered}[/tex]The above equation is in slope-intercept form, therefore, the slope of the given line is:
[tex]-\frac{3}{5}\text{.}[/tex]Now, recall that two lines are parallel if they have the same slope.
Answer: Option a.