The equation of a line is:
[tex]y-y_1=m(x-x_1)[/tex]where (x1,y1) is a point in the line and m is the slope.
In our case we have two points but we don't have the slope yet, to find it we need to remember that the slope is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Then, in our case:
[tex]\begin{gathered} m=\frac{1-(-2)}{4-2} \\ =\frac{1+2}{2} \\ =\frac{3}{2} \end{gathered}[/tex]Then, the equation of the line is:
[tex]\begin{gathered} y-1=\frac{3}{2}(x-4) \\ 2y-2=3x-12 \\ 3x-2y=-2+10 \\ 3x-2y=10 \end{gathered}[/tex]Therefore the answer is A.