Question

A parabola opening up or down has vertex (0, 1) and passes through (8, -3). Write its equation invertex form.

Answer 1

Explanation

The parabola in vertex form is given as

$y=a(x-h)^2+k$

Where (h,k) is the vertex.

$y=a(x-0)^2+1$

Therefore, since the parabola passes through (8,-3)

We will have;

$\begin{gathered} -3=a(8)^2+1 \\ -3=64a+1 \\ 64a=-4 \\ a=-\frac{4}{64} \\ a=-\frac{1}{16} \end{gathered}$

Therefore;

Answer:

$y=-\frac{1}{16}(x-0)^2+1$