Question

How much rain more rain on the average does Tucson get than Yuma

Answer 1

$13\text{ }\frac{13}{20}$

Explanation

to solve this we need to do a subtaction

difference= amount in Tucson - amount in Yuma

Step 1

convert the mixed numbers into fractions,

remember how:

$a\text{ }\frac{b}{c}=\frac{(a\cdot c)+b}{c}$

hence

$\begin{gathered} 11\frac{1}{4}=\frac{(11\cdot4)+1}{4}=\frac{45}{4} \\ 2\frac{2}{5}=\frac{(2\cdot5)+2}{5}=\frac{12}{5} \end{gathered}$

then Let

$\begin{gathered} \text{Amount in Tucson=}\frac{45}{4} \\ \text{Amount in Yuma =}\frac{12}{5} \end{gathered}$

Step 2

now, we can proceed to do the subtraction of the fractions:

remember

$\frac{a}{b}-\frac{c}{d}=\frac{ad-bc}{bd}$

hence,

difference= amount in Tucson - amount in Yuma

replace and calculate

$\begin{gathered} D=\frac{45}{4}-\frac{12}{5} \\ D=\frac{45\cdot5+4\cdot12}{20} \\ D=\frac{225+48}{20} \\ D=\frac{273}{20} \end{gathered}$

we can simplyfy the answer

$\begin{gathered} D=\frac{273}{20}=13\frac{13}{20} \\ \text{because} \\ \frac{(13\cdot20)+13}{20}=\frac{273}{20} \end{gathered}$

the answer is

$13\text{ }\frac{13}{20}$

I hope this helps you