Respuesta :

The given equation is:

[tex]3y^2=432[/tex]

Divide both sides of the equation by 3:

[tex]\begin{gathered} \frac{3y^2}{3}=\frac{432}{3} \\ y^2=144 \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} y=\pm\sqrt{144} \\ y=\pm12 \end{gathered}[/tex]

Hence

y = -12 or y = 12

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