Okay, here we have this:
Considering the provided information, we are going to find the requested polynomial function, so we obtain the following:
Then let us remember that a second degree polynomial has the following form:
f(x)=ax^2+bx+c, where a, b and c are integers.
So replacing with the given point we get:
-9=a(0)^2+b(0)+c
-9=0+0+c
-9=c
Therefore any polynomial of the form ax^2+bx+c with c=-9 will pass through the given point, so if we take for example a=1, b=1 and c=-9, we obtain the following graph:
f(x)=1x^2+1x-9:
