Respuesta :

The question is given to be:

[tex]\frac{3^5}{3^8}[/tex]

Applying the law of indices:

[tex]\frac{a^m}{a^n}=a^{m-n}[/tex]

Therefore, we have the expression to be:

[tex]\frac{3^5}{3^8}=3^{5-8}=3^{-3}[/tex]

Recall the law of negative exponents:

[tex]a^{-m}=\frac{1}{a^m}[/tex]

Therefore, the expression becomes:

[tex]3^{-3}=\frac{1}{3^3}=\frac{1}{3\times3\times3}=\frac{1}{27}[/tex]

The expression is also equivalent to:

[tex](\frac{1}{3})^3[/tex]

Since:

[tex](\frac{1}{3})^3=\frac{1^3}{3^3}=\frac{1}{27}[/tex]

ANSWER

The correct options are OPTION C, OPTION E, and OPTION F.

RELAXING NOICE
Relax