Answer:
[tex]\lvert u\rvert=17[/tex]Step-by-step explanation:
Given the vector, u =<4, -1>, determine the magnitude.
The magnitude of a vector is represented as:
[tex]\begin{gathered} \lvert{v}\rvert=\sqrt{v1^2+v2^2} \\ where, \\ v=\langle v1,v2\rangle \end{gathered}[/tex]Therefore, for the given vector:
[tex]\begin{gathered} \lvert{u}\rvert=\sqrt{4^2+(-1)^2} \\ \lvert{u}\rvert=\sqrt{16+1} \\ \lvert{u}\rvert=\sqrt{17} \end{gathered}[/tex]