Respuesta :

Answer:

[tex]\lvert u\rvert=17[/tex]

Step-by-step explanation:

Given the vector, u =<4, -1>, determine the magnitude.

The magnitude of a vector is represented as:

[tex]\begin{gathered} \lvert{v}\rvert=\sqrt{v1^2+v2^2} \\ where, \\ v=\langle v1,v2\rangle \end{gathered}[/tex]

Therefore, for the given vector:

[tex]\begin{gathered} \lvert{u}\rvert=\sqrt{4^2+(-1)^2} \\ \lvert{u}\rvert=\sqrt{16+1} \\ \lvert{u}\rvert=\sqrt{17} \end{gathered}[/tex]

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