Question

If a 48-pound beef round is roasted, and 9 pounds are lost through shrinkage, what percent of the round is lost through shrinkage?

Answer 1

we can write an equation

you multiply the total pounds by the percent lost to find the lost pounds

then

$48\times x=9$

where x is the percent lost, then solve for x

$\begin{gathered} x=\frac{9}{48} \\ \\ x=\frac{3}{16}=0.1875 \end{gathered}$

multiply by 100 to find on percent form

$0.1875\times100=18.75$

Percent is 18.75%