Question

Suppose that the function h is defined, for all real numbers, as follows.1if x #2h(x)=if x=2Find h(-5), h (2), and h (4).h(-5) = 08h (2) = 0h(4) = 0010XG?

Answer 1

Given,

The expression of the function is,

$h(x)=\begin{cases}{-\frac{1}{4}x-1,\text{ if x}2} \\ {} \\ 1,\text{ if x }=2{}\end{cases}$

The value of h(-5) is,

$h(-5)=-\frac{1}{4}(-5)-1=\frac{5}{4}-1=\frac{5-4}{4}=\frac{1}{4}$

The value of h(2) is,

$h(2)=1$

The value of h(4) is,

$undefined$