Question

WILL GIVE BRAINLISTD D 14.(08.03 LC)A set of equations is given below:Equation C: y = 3x + 7Equation D: y = 3x + 2How many solutions are there to the given set of equations? (1 point)Infinitely many solutionsOne solutionNo solutionTwo solutions

Answer 1

Hello!

We have two equations, let's write them below:

$\begin{cases}y=3x+7 \\ y=3x+2\end{cases}$

Notice that we know the value of Y twice, but they're different (3x +7 ≠ 3x +2). So, probably we will have a problem. Let's solve it by substitution:

In equation D (second), I'll replace 'y' with the value contained in equation C (first), okay?

$\begin{gathered} y=3x+2 \\ 3x+7=3x+2 \\ \cancel{3x}+7=\cancel{3x}+2 \\ 7\ne2 \end{gathered}$

As I mentioned before, we have a problem here: the values of y are different.

So, this set of equations has no solution.