Question

Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p.n=125, p=0.78The mean, u, is(Round to the nearest tenth as needed.)The variance, op.is(Round to the nearest tenth as needed.)The standard deviation, o, is(Round to the nearest tenth as needed.)esticpartEnter your answer in each of the answer boxes.

Answer 1

mean is given by

$\mu\text{ = np}$

mean = 125 x 0.78 = 97.5

Variance is given by

$\text{Varience = np (1 - p)}$

=> 125 x 0.78 (1- 0.78)

=>97.5 (0.22)

=>21.45

Variance => 21.5 (to the nearest tenth)

Standard deviation is given by

$\begin{gathered} \text{Standard variation = }\sqrt[]{variance} \\ =\text{ }\sqrt[]{21.5} \\ =4.64 \\ \end{gathered}$

Standard deviation = 4.6 (to the nearest tenth)