Respuesta :

Given expression:

[tex]2rs\text{ - 4rt - 6t + 3s}[/tex]

Collect like terms:

[tex]=\text{ 2rs - 4rt - 6t + 3s}[/tex]

Next, we bring the common terms:

[tex]=\text{ 2r(s - 2t) -3(2t - s)}[/tex]

Re-writing the expression:

[tex]=\text{ -2r(2t - s) -3(2t -s)}[/tex]

Since we have a common term on either side of the negative sign, we can write:

[tex]=\text{ (-2r -3)(2t-s)}[/tex]

Answer:

[tex]=\text{ (-2r-3)(2t -s)}[/tex]

Let us verify the answer:

[tex]\begin{gathered} (-2r\text{ -3)(2t-s)} \\ =-2r(2t\text{ -s) -3(2t -s)} \\ =\text{ -4rt + 2rs -6t + 3s} \end{gathered}[/tex]

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