We have a line of which we know the slope m = -10/11 and one point (x0,y0) = (-11,10).
We have to find its equation in slope-intercept form.
We can start by writing the equation in slope-point form with the information we have and rearrange to express it in slope-intercept form:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-10=-\frac{10}{11}(x-(-11)) \\ y-10=-\frac{10}{11}(x+11) \\ y=-\frac{10}{11}x-\frac{10}{11}\cdot11+10 \\ y=-\frac{10}{11}x-10+10 \\ y=-\frac{10}{11}x \end{gathered}[/tex]
The equation in slope-intercept form is y = -(10/11)*x.
Answer: y = -(10/11)*x
