Question

find the x-intercepts of the function f(x)=x²+6x+8

Answer 1

given the function:

$f(x)=x^2+6x+8$

to find the x-intercepts, we have to set f(x) equal to 0 and solve for x.

We have the following:

$\begin{gathered} f(x)=0 \\ \Rightarrow x^2+6x+8=0 \\ \Rightarrow(x+2)(x+4)=0 \\ \Rightarrow x_1=-2,x_2=-4 \end{gathered}$

therefore, the x-intercepts of f(x) are the points (-2,0) and (-4,0)