The slope-point form of the line equation is
[tex]y-b=m(x-a)[/tex]If we replace the slope m=-1/2 and the point (4,-5), that is, a=4, b=-5, then we obtain
[tex]\begin{gathered} y-(-5)=-\frac{1}{2}(x-4) \\ y+5=-\frac{1}{2}x+2 \\ y=-\frac{1}{2}x-3 \end{gathered}[/tex]This is the slope-intercept form of the equation, we can also write it in the next way
[tex]\begin{gathered} y=-\frac{1}{2}x-3 \\ 2y=-x-6 \\ x+2y=-6 \end{gathered}[/tex]
