Question

The table gives the temperature (in F) in five cities at 6 a.m. on the same day. Use the table to answer the questions CityTemperature(F)Buffalo-6Dayton48Atlanta64Winnipeg -16Juneau-26(a)How much higher was the 6a.m. temperature in Dayton than in Buffalo?(b)By noon, the temperature in Juneau had risen by 13F .What was the temperature there at noon?

Answer 1

Solution

Question A:

- The Buffalo temperature was -6° F and the temperature at Dayton was 48° F.

- Thus, we can find how much more the temperature in Dayton is compared to the temperature at Buffalo by subtracting both temperatures. That is,

$\begin{gathered} \text{ Temperature in Dayton - Temperature in Buffalo} \\ 48°F-(-6°F)=48°F+6°F=54°F \end{gathered}$

- The temperature at Dayton is 54° F higher than the temperature in Buffalo.

Question B:

- The noon temperature in Juneau has increased by 13℉ by noon. This implies that we should add this increase in temperature to the initial temperature in Juneau when it was 6 am.

- This is done below:

$\begin{gathered} \text{ Juneau temperature by noon is} \\ -26℉+13℉=-13℉ \end{gathered}$

- The temperature in Juneau at noon is -13℉

Final Answer

- The temperature at Dayton is 54° F higher than the temperature in Buffalo.

- The temperature in Juneau at noon is -13℉