Consider that the area (A) of a square with side 's' is given by the formula,
[tex]A=s^2[/tex]Given that the area is 49 sq. meters,
[tex]A=49[/tex]Substitute the values and solve for the side 's' as follows,
[tex]\begin{gathered} s^2=49 \\ s=\sqrt[]{49} \\ s=\pm7 \end{gathered}[/tex]But 's' is the side of the square, which cannot be negative.
So we have to neglect the negative value, and consider the positive value,
[tex]s=7[/tex]Thus, the side of the given square is 7 meters .