By the logarithm quotient rule:
[tex]\ln \mleft(\frac{x}{y}\mright)=\ln (x)-\ln (y)[/tex]
The given could then be rewritten as:
[tex]\begin{gathered} \ln \mleft(\frac{5x-3}{x+3}\mright)\text{ Given} \\ \\ \text{the numerator is }5x-3,\text{ and the denominator is }x+3 \\ \text{therefore we could rewrite it as} \\ \ln (5x-3)-\ln (x+3)\text{ (final answer)} \end{gathered}[/tex]
