The mass of the block. m=0.6 kg
The displacement of the spring, x=0.15 m
Total force applied on the spring from the mass is given by,
[tex]F=mg\text{ }\rightarrow\text{ (i)}[/tex]Where g is the acceleration due to gravity.
The restoring force of the spring is given by,
[tex]F=kx\text{ }\rightarrow\text{ (ii)}[/tex]Where k is the spring constant
Thus, from equation (i) and equation (ii),
[tex]\begin{gathered} mg=kx \\ \Rightarrow k=\frac{mg}{x} \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} k=\frac{0.6\times9.8}{0.15} \\ =39.8\text{ N/m} \end{gathered}[/tex]Thus the force constant of the spring is 39.8 N/m
